4.9t^2-7,5t+10=

Solution for 4.9t^2-7,5t+10= equation:

4.9t^2-7.5t+10=

We move all terms to the left:

4.9t^2-7.5t+10-()=0

We add all the numbers together, and all the variables

4.9t^2-7.5t=0

a = 4.9; b = -7.5; c = 0;
Δ = b2-4ac
Δ = -7.52-4·4.9·0
Δ = 56.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7.5)-\sqrt{56.25}}{2*4.9}=\frac{7.5-\sqrt{56.25}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7.5)+\sqrt{56.25}}{2*4.9}=\frac{7.5+\sqrt{56.25}}{9.8}
$